Answer:
0.1M
Explanation:
We'll begin by writing a balanced equation for the reaction between HCl and NaOH. This is illustrated below:
HCl + NaOH —> NaCl + H2O
From the above equation, we obtained:
nA (mole of the acid) = 1
nB (mole of the base) = 1
Data obtained from the question include:
Ma (Molarity of the acid ) = 0.12M
Va (volume of the acid) = 21.35cm3
Mb (Molarity of the base) =?
Vb (volume of the base) = 25.55cm3
Using the equation MaVa/MbVb = nA/nB, the molarity of the base can be obtained as follow:
MaVa/MbVb = nA/nB
0.12 x 21.35 / Mb x 25.55 = 1
Cross multiply to express in linear form.
Mb x 25.55 = 0.12 x 21.35
Divide both side by 25.55
Mb = (0.12 x 21.35)/25.55
Mb = 0.1M
Therefore, the molarity of the base (NaOH) is 0.1M
