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Which is an equation of the line containing the points (4, 10) and (6, 11) in standard form?
A. –x + 2y = 16

B. x + 2y = 24

C. x – 2y = –16

D. 2x – y = –2

Respuesta :

igoroleshko156

Answer:

Option C, x - 2y = -16

Step-by-step explanation:

Step 1:  Find the slope

[tex]m = (y_2 - y_1) / (x_2 - x_1)[/tex]

[tex]m = (11 - 10) / (6 - 4)[/tex]

[tex]m = 1 / 2[/tex]

Step 2:  Plug in into point-slope form

[tex](y - y_1) = m(x - x_1)[/tex]

[tex](y - 10) = 1/2(x - 4)[/tex]

[tex]y - 10 = 1/2x - 2[/tex]

Step 3:  Solve for x

[tex]y - 10 + 2 = 1/2x - 2 + 2[/tex]

[tex](y - 8) * 2/1 = 1/2x * 2/1[/tex]

[tex]2y - 16 = x[/tex]

Step 3:  Put the variables on one side

[tex]2y - 16 - 2y = x - 2y[/tex]

[tex]-16 = x - 2y[/tex]

[tex]x - 2y = -16[/tex]

Answer: Option C, x - 2y = -16

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