Answer:
the list of forces from greatest to least is Y, W, X, Z
Explanation:
Given data:
5 pairs of charged plates with force between each pair as : F, W, X,Y, Z
Also given are the charges q1 and q2 of plates in each pair and the distances between them (refer attachment)
To find: to arrange the force from greatest to least.
Initial step is to calculate the force value using the given data of charges and distance between plates.
We know that the force between two charged plates is given by the formula:
F = [tex]\frac{kq1q2}{r^{2} }[/tex]
where,
q1 and q2 are charge of the two plates
r is the distance between two plates
k is coulomb constant
Since the problem involves comparison of forces, the k values is not necessarily discussed.
Now we have to calculate force values
F = [tex]\frac{kq^{2} }{d^{2} }[/tex]
W = [tex]\frac{2kq^{2} }{d^{2} }[/tex]
X = [tex]\frac{kq^{2} }{4d^{2} }[/tex]
Y = [tex]\frac{3kq^{2} }{d^{2} }[/tex]
Z = [tex]\frac{kq^{2} }{9d^{2} }[/tex]
Assume values of q = 1 and d = 2, we get
F = 0.5k
W = 0.5k
X = 0.0625k
Y = 0.75k
Z =0.025k
F and W are though same, the calculated force value shows W = 2F
Hence W is greater than F.
Therefore, the list of forces from greatest to least is Y, W, F, X, Z
Hence answer is : Y, W, X, Z
Answer:
B) Y,W,X,Z
Explanation:
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