grm42192
contestada

What is the final volume (L) of a 1.00 L system at 315 K and 1.10 atm if STP conditions are established?

Respuesta :

Eduard22sly

Answer:

0.95L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 1L

T1 (initial temperature) = 315K

P1 (initial pressure) = 1.10 atm

T2 (final temperature) = stp = 273K

P2 (final pressure) = stp = 1atm

V2 (final volume) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:

P1V1/T1 = P2V2/T2

1.1 x 1/315 = 1 x V2/273

Cross multiply to express in linear form.

315 x V2 = 1.1 x 273

Divide both side by 315

V2 = (1.1 x 273) /315

V2 = 0.95L

Therefore, the final volume of the system if STP conditions are established is 0.95L

Cricetus

The final volume of a 1.00 L system will be "0.95 L".

Gas equation

According to the question,

Initial temperature, T₁ = 315 K

Final temperature, T₂ = 273 K

Initial pressure, P₁ = 1.10 atm

Final pressure, P₂ = 1 atm

Initial volume, V₁ = 1 L

By using the gas equation,

→   [tex]\frac{P_1 V_1}{T_1} =\frac{P_2 V_2}{T_2}[/tex]

By substituting the values,

    [tex]\frac{1.1\times 1}{315} =\frac{1\times V_2}{273}[/tex]

By applying cross-multiplication,

315 × V₂ = 1.1 × 273

         V₂ = [tex]\frac{1.1\times 273}{315}[/tex]

              = 0.95 L

Thus the answer above is right.

Find out more information about volume here:

https://brainly.com/question/20348074

Otras preguntas