Answer:
Velocity of proton will be equal to 4500 m/sec
Explanation:
We have given that proton moves right angles through a magnetic field
So angle between magnetic field and velocity of proton is [tex]\Theta =90^{\circ}[/tex]
Magnetic field B = 0.025 Tesla
Charge on proton [tex]e=1.6\times 10^{-16}C[/tex]
Magnetic force on the proton is given [tex]F=1.8\times 10^{-14}N[/tex]
Magnetic force on a moving charge particle is equal to [tex]F=qvBsin\Theta[/tex]
So [tex]1.8\times 10^{-14}=1.6\times 10^{-16}\times v\times 0.025\times sin90^{\circ}[/tex]
v = 4500 m/sec
So velocity of proton will be equal to 4500 m/sec
