Work done is 0.442J
Explanation:
Given:
Spring constant, k = 33 N/m
Distance, x₁ = 0.15m
Additional distance, x₂ = 0.072 m
Total distance = 0.15 + 0.072 m
= 0.222 m
Work done, W = ?
We can calculate work done by the formula
[tex]W = \frac{1}{2}kx_2^2 - \frac{1}{2}kx_1^2[/tex]
On substituting the value we get:
[tex]W = \frac{1}{2}k [(x_2)^2 - (x_1)^2]\\ \\W = \frac{1}{2} X 33[(0.222)^2 - (0.15)^2]\\ \\W = \frac{1}{2}X 33 [ 0.0493 - 0.0225]\\ \\W = 0.442 J[/tex]
Therefore, work done is 0.442J
