Answer:
Correct answer: V₂ = 1.79 m/s
Explanation:
Given:
m₁ = 32 kg the mass of the first student
V₁ = 2.4 m/s speed of the first student after pushing
m₂ = 43 kg the mass of the second student student
V₂ = ? speed of the second student after pushing
I₁ = m₁ · V₁ impulse of the first student
I₂ = m₂ · V₂ impulse of the second student
Under the law of impulse maintenance, the total impulse of an object must be constant over time.
Since the total impulse before pushing was equal to zero it must be afterwards.
I₁ + I₂ = 0 ⇒ I₂ = - I₁ ⇒ V₂ = - V₁
Given that the impulses are vectors a sign minus ahead of the first pulse mean, they are opposite directions.
m₂ · V₂ = m₁ · V₁ ⇒ V₂ = (m₁ · V₁) / m₂ = (32 · 2.4) / 43 = 1.79 m/s
V₂ = 1.79 m/s
God is with you!!!
