The probability of the pointer lands on red(R) both spin = [tex]\frac{1}{36}[/tex]
Step-by-step explanation:
Given,
The number of parts = 6
The pointer is spun twice.
To find the probability of the pointer lands on red(R) both spin.
Formula
Probability of an event = number of required outcomes ÷ the total number of outcomes.
P(A and B) = P(A)×P(B)
Now,
For one spin,
A = RED comes.
For second spin,
B = RED comes
So,
P(A) = [tex]\frac{1}{6}[/tex] and P(B) = [tex]\frac{1}{6}[/tex]
Then,
P(A and B) = [tex]\frac{1}{6}[/tex] × [tex]\frac{1}{6}[/tex] = [tex]\frac{1}{36}[/tex]
Hence, the probability of the pointer lands on red(R) both spin = [tex]\frac{1}{36}[/tex]
