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caylus
Hello,

1) you may draw a right triangle ABC (3,4,5) and measure the angle opposed to side of 4.

2) you may use
[tex]as\ x\ \textgreater \ 1,\\\\ arctg\ x= \dfrac{\pi}{2} - \dfrac{1}{x}+\dfrac{1}{3x^3}-\dfrac{1}{5x^5} +....[/tex]

arctg(4/3)=0,92729521800161223242851246292243....

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meerkat18
To find the arc tangent of the 4 over 3 with out using calculator, you have to use the theorem of trigonometric function in solving this you have to place a variable that could be the output so the answer would be 0.87. I hope you are satisfied with my answer and feel free to ask for more 

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