Respuesta :

Hagrid
It's likely what's wanted is

LiLi2++2e−

The reason is because IEs are usually reported from the neutral atom, that is, IE2 is the energy required to remove two electrons from a neutral Li atom, as above, rather than the additional energy required to remove one more electron from an Li+ cation.

Answer:

Li^+ (g) -----> Li^2+ (g)+ e^-

Explanation: