Respuesta :
Answer:
ac = 0.01071 m = 10.71 mm
Explanation:
Given:-
- The thickness of plate, t = 24.2 mm
- The yield strength of metal alloy, σy = 545 MPa
- The fracture toughness, Kic = 20.0 MPa-√m
- The geometrical criticality, Y = 1.0
- Factor of design, nd = 0.2
Find:-
Calculate the critical length of a surface flaw
Solution:-
- We are to determine the minimum critical length ( ac ) for the design stress ( σd ) that leads to failure of the plate with thickness ( t ).
- The relation for the critical length ( ac ) depends on the material intrinsic properties i.e Fracture toughness - ( Energy required for the material to fracture ) and the design yield strength ( σd = nd*σy ).
- The relation is given below:
ac = [ Kic / Y*σd ] ^2 * ( 1 / π )
ac = [ Kic / Y*σy*nd ] ^2 * ( 1 / π )
ac = [ 20.0*5 / 1*545 ] ^2 * ( 1 / π )
ac = 0.01071 m = 10.71 mm
Answer: The minimum critical length ( ac ) for the metal alloy subjected to the given design stress is ( 10.71 mm ) for fracture.
