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If a bag contains 6 red balls, 4 green balls, and 3 blue balls. If we choose a ball, then another ball without putting the first one in the bag, what is the probability that the first ball is green anda the second one red

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crsjr

hello,

red 6

green 4

blue 3

  • first ball is green:

[tex] \frac{4}{13} [/tex]

  • second ball is red:

[tex] \frac{6}{12} = \frac{1}{2} [/tex]

The probability that these two events happen at the same time is:

[tex] \frac{4}{13} \times \frac{1}{2} = \frac{4}{26} = \frac{2}{13} [/tex]

[tex] \boxed{crsjr} [/tex]

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