Answer:
49.4 degrees
Step-by-step explanation:
In Triangle AXY,
[tex]Tan 35^0=\frac{|XY|}{60} \\|XY|=60*Tan 35^0=42.01\:feet\\$Therefore, Height of the pole=42.01 \:feet[/tex]
We want to determine the angle of elevation from the point Vera is standing to the top of the flagpole, which is the angle at V in the diagram.
In Triangle XVY
|VY|=36 feet
[tex]Tan \theta=\frac{|XY|}{|VY|} \\Tan \theta=\frac{42.01}{36}\\ \theta=arctan(\frac{42.01}{36})\\ \theta=49.4^0[/tex]
Therefore, the angle of elevation from the point Vera is standing to the top of the flagpole is 49.4 degree to the nearest tenth of a degree.
