Respuesta :
Answer:
Explanation:
Given that,
The pressure around the diver is
P = 10^5 Pa,
At a height of 10m
h = 10m
We want to find the force per square centimeter of the diver body
Pressure = force / Area
Force / Area = pressure,
And since the pressure is given
Then,
Force / Area = 10^5 Pa
Since 1 pascal = 1 N/m²
Force / Area = 10^5 N/m²
Since, we know that, 100cm = 1m
(100cm)² = (1m)²
10000cm² = 1m²
10⁴cm² = 1m²
Then,
Force / Area = 10^5 N/m² × 1m²/10⁴cm²
Force / Area = 10 N/cm²
The required force per unit area is 10 N /cm²
Answer:
ΔP = 10 N / cm^2
Explanation:
Solution:-
- The pressure on an object placed inside any fluid changes linearly with the depth of fluid above the object.
- A fluid has its density. In our case we will take the density of water:
ρw = 1000 kg/m^3
- The pressure ( P ) exerted on an object at the depth of ( h ) is given below:
P = ρ*g*h
Where,
g: The gravitational acceleration constant = 9.81 m/s^2
- The differential expression relating the change in pressure and change in depth of the object under the fluid.
ΔP = ρ*g*Δh
- We are given that the scuba diver experiences an increase in pressure of:
ΔP = 10^5 N / m^2
- We are to determine the change in pressure - ( change in force per square centimetre )
- The conversion of units would be as follows:
ΔP = 10^5 [ N / m^2 ] * [ m^2 / (100cm)^2 ]
ΔP = 100000/10000 [ N / m^2 ] * [ m^2 / cm^2 ]
ΔP = 10 N / cm^2
