A course in the shape of a triangle consists of a running path, bike path, and skateboarding path. The bike path is 51 meters long and the skateboarding path is 64 meters long. If the angle between the running and bike paths is 78°, find the angle between the running and skateboarding paths to the nearest tenth of a degree.

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Answer:

51.2

Step-by-step explanation:

Sin^{-1}(((51*(sin(78)))/64)) = 51.2

The angle between the running and skateboarding paths is 51.2 degrees.

What is a triangle?

'A triangle is a three-sided polygon that consists of three edges and three vertices. The most important property of a triangle is that the sum of the internal angles of a triangle is equal to 180 degrees. This property is called angle sum property of triangle.'

According to the given problem,

Side A = 51 meters

Side B = 64 meters

Given, angle = 78°

We know, according to the law of sines,

[tex]\frac{a}{sinA}=\frac{b}{sinB}[/tex]

⇒ [tex]\frac{51}{sinA}=\frac{64}{sin78}[/tex]

⇒ [tex]\frac{sinA}{51} = \frac{sin78}{64}[/tex]

⇒ sin A = [tex]\frac{51*sin78}{64}[/tex]

⇒ sinA = 0.78

⇒ A = [tex]sin^{-1} (0.78)[/tex]

⇒ A = 51.2°

Hence, we can conclude, the angle between the running and skateboarding paths is 51.2 degrees.

Learn more about triangles here: https://brainly.com/question/2773823

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