Answer: The molarity of solution is 0.584 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
mass of solute (sugar) = [tex]\frac{\text {given mass}}{\text {Molar Mass}}=\frac{10.0g}{342g/mol}=0.0292[/tex]
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{0.0292\times 1000}{50.0}=0.584mole/L[/tex]
Therefore, the molarity of solution is 0.584 M
0.581 M is the molarity of a 50.0 ml solution containing 10.0 grams of table sugar.
Molarity of a solution is defined as the no. of moles of solute present in per liter of solution, and it can be expressed as:
M = n / V
And moles can be defined as n = W / M
or M = W × 1000 / M × Vₓ, where
W = given mass of sugar (C₁₂H₂₂O₁₁) = 10 g
M = molar mass of C₁₂H₂₂O₁₁ sugar = 342.3 g/mole
Vₓ = volume of solution in ml = 50 ml
Putting all these values in the above equation, we get
M = (10 × 1000) / (342.3 × 50)
M = 0.581 mole/L
Hence, molarity of the solution is 0.581 M.
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