13. Find the area of a circle with a
circumference of 26 (pi)feet.
16. Find the circumference of a
circle with an area of 289(pi)mm2.
17. Find the circumference of a
circle with an area of 113.1 in 2
18. Find the area of a circle with a
circumference of 131.95 meters.

13 Find the area of a circle with a circumference of 26 pifeet 16 Find the circumference of a circle with an area of 289pimm2 17 Find the circumference of a cir class=

Respuesta :

Answer:

13. 169π ft²

16. 34π mm

17. 12π in

18. 441π m²

Step-by-step explanation:

Circumference of a circle is calculated as follows:

C = 2π*r

Area of a circle is calculated as follows:

A = π*r²

where r is the radius of the circle

13. circumference of the circle: 26π ft

Then, its radius is:

26π = 2π*r

r = 26π/(2π) = 13 ft

A = π*13² = 169π ft²

16. area of the circle: 289π mm²

Then, its radius is:

289π = π*r²

r = √289

r = 17 mm

C = 2π*17 = 34π mm

17. area of the circle: 113.1 in²

Then, its radius is:

113.1 = π*r²

r = √(113.1/π)

r = 6 in

C = 2π*6 =  12π in

18. circumference of the circle: 131.95 m

Then, its radius is:

131.95 = 2π*r

r = 131.95/(2π)

r = 21 m

A = π*21² = 441π m²

13. The area is 169π ft².

14. The circumference is 34π mm.

15. The circumference is 12 π in.

16. The area is 441π m².

Calculation of the area & circumference:

Since

The circumference of a circle should be

C = 2π*r

And, Area of a circle should be

A = π*r²

Here, r is the radius of the circle

Now

13.

Since the circumference of the circle is 26π ft

So, its radius is:

26π = 2π*r

r = 26π/(2π) = 13 ft

So,

A = π*13²

= 169π ft²

16. Since area of the circle is 289π mm²

So, its radius is:

289π = π*r²

r = √289

r = 17 mm

So,

C = 2π*17

= 34π mm

17. Since area of the circle is 113.1 in²

So, its radius is:

113.1 = π*r²

r = √(113.1/π)

r = 6 in

So,

C = 2π*6

=  12π in

18. Since circumference of the circle: 131.95 m

So, its radius is:

131.95 = 2π*r

r = 131.95/(2π)

r = 21 m

So,

A = π*21²

= 441π m²

learn more about the area here: https://brainly.com/question/17397308