Answer:
At a temperature of 251.15 K
Explanation:
To calculate this temperature, we make use of the ideal gas equation
Mathematically;
PV = nRT
where P is the pressure given as 2.4atm
V is the volume which is the volume of the cylinder at 5.2L
n is the number of moles which is 0.606 according to the question
R is the molar gas constant which is 0.082 L atm K^-1 mol^-1
T is the temperature which we are looking for according to the question
Rearranging the equation, we have ;
T = PV/nR
Plugging the values;
T = (2.4 * 5.2)/(0.606 * 0.082)
T = 12.48/0.049692
T = 251.15 K
