davidv0490
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PLEASE HELP FAST!!!

On a coordinate plane, an exponential function approached y = 0 in quadrant 2 and increases into quadrant 1. It crosses the x-axis at (0, 2).
What is the initial value of the exponential function shown on the graph?

0
1
2
4

Respuesta :

I believe the answer is 4

The initial value of the exponential function shown on the graph should be 2.

Calculation of the initial value:

Since The initial value of an exponential function  should be considered as the y-intercept of the function

Here, The initial value of the exponential function should be  2.

Also, the exponential function crosses the y-axis at point (0,2)

This means that, the value of y at the time when x = 0 is 2

Therefore, The initial value of the exponential function shown on the graph should be 2.

Learn more about exponential function here: https://brainly.com/question/12394974

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