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Suppose on a certain test, fifty students earn a perfect score and fifty students earn a zero. Determine the mean grade and standard deviation among the one hundred students.

A. Mean grade among the one hundred students is a0

B. Standard deviation: a1

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Answer:

Mean: 50

Standard Deviation: 50

Step-by-step explanation:

The mean is found by adding up all the numbers and dividing them by the total number of numbers. In this case it was 5000/100 which equals  50.

Standard deviation is the distance from each point to the mean. The only scores given were 100 (perfect score) and 0. The distance from 100 to 50 (the mean) is 50 and the distance from 0 to 50 (the mean) is 50, therefore the standard deviation is 50.