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30.0 grams of NaNO3 is dissolved in water to make a 5.00 L solution. What is the molarity of the solution?

Respuesta :

emaikwuvictor

Answer:

Molarity= 0.071M

Explanation:

Molar mass of NaNO3= 23+14+(16*3)=85

n= m/M = 30/85= 0.353mol

V= 5L

Applying

n= CV

0.353= C×5

Simplify

C= 0.071M

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