In a bag of 60 candies, 36 are green and 45 have caramel in them. If the events of picking a green candy and picking a candy with caramel are independent, what is the probability of selecting two candies where the first is green and the second has caramel? Express your answer as a fraction in simplest form.

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Answer:

9/20

Step-by-step explanation:

Total number of candies =60

Number of Green candies, n(G)=36

Number of candies with caramel, n(C)=45

Since the events are independent, the probability of selecting two candies where the first is green and the second has caramel is given by:

P(GC)=P(G) X P(C)

[tex]=\dfrac{n(G)}{n(S)} X \dfrac{n(C)}{n(S)} \\=\dfrac{36}{60} X \dfrac{45}{60}\\ =\dfrac{9}{20}[/tex]

The probability in its lowest form is 9/20.