PLEASE HELP THIS IS TIMED !!!!!

Use the graph of f(x) to explain the relationship between the real zeros of f(x) and its intercept(s).

A. ) f(x) has one real zero at –2 because the graph of the function has an intercept at (0, –2).
B. ) f(x) has two real zeros at –4 and –2 because the graph of the function has intercepts at (–4, 0) and (0, –2).
C. ) f(x) has no real zeros because the graph of the function does not pass through (0, 0).
D. ) f(x) has one real zero at –4 because the graph of the function has an intercept at (–4, 0).

PLEASE HELP THIS IS TIMED Use the graph of fx to explain the relationship between the real zeros of fx and its intercepts A fx has one real zero at 2 because t class=

Respuesta :

Answer:

C. ) f(x) has no real zeros because the graph of the function does not pass through (0, 0).

Step-by-step explanation:

According to L'Hospital's Rule, this is true.