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Quincy uses the quadratic formula to solve for the values of x in a quadratic equation. He finds the solution, in simplest radical form, to be x = [tex]\frac{-3± \sqrt{-19}}{2}[/tex].

Which best describes how many real number solutions the equation has?

A. Zero, because the discriminant is negative.
B. Zero, because the discriminant is not a perfect square.
C. One, because the negative and the minus cancel each other out.
D. Two, because of the ± symbol.

Respuesta :

amna04352

Answer:

A. Zero, because the discriminant is negative.

Step-by-step explanation:

Square root of a negative number is not real, hence no real roots

The real number solutions of the equation will be zero, because the discriminant is negative. Then the correct option is A.

What is the solution of the quadratic equation by formula method?

The quadratic equation is given as ax² + bx + c = 0.

Then the solution is given as

[tex]\rm x = \dfrac{-b\pm \sqrt{b^2 - 4ac}}{2a}[/tex]

Quincy uses the quadratic formula to solve for the values of x in a quadratic equation. He finds the solution, in the simplest radical form, to be

[tex]\rm x = \dfrac{-3\pm \sqrt{-19}}{2}[/tex]

The discriminant is given as

D = b² – 4ac

If the value of the discriminant is greater than zero, then the real and distinct solution.

If the value of the discriminant is equal to zero, then the real and same solution.

And if the value of the discriminant is less than zero, then the imaginary solution.

The real number solutions of the equation will be zero, because the discriminant is negative.

Then the correct option is A.

More about the solution of the quadratic equation link is given below.

https://brainly.com/question/17376136

#SPJ2

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