A new car is purchased for $49,000 and over time its value depreciates by one half every 5 years. What is the value of the car 21 years after it was purchased, to the nearest hundred dollars?

Respuesta :

Answer: y=10700

Step-by-step explanation:

Y=a(1/2) ^t/h

A= 49000 h=5 t=11

Plug in: y=49000(1/2)^11/5

Y=10664.2444004

Y=10700

The value of the car after 21 years is $2666.06.

Important information:

  • Initial value of car = $49000
  • Value depreciates by one-half every 5 years.
  • Time = 21 years

Depreciations:

According to the given information, the value of the car after n years is:

[tex]V(n)=49000\left(\dfrac{1}{2}\right)^{\frac{n}{5}}[/tex]

Substitute [tex]n=21[/tex].

[tex]V(n)=49000\left(\dfrac{1}{2}\right)^{\frac{21}{5}}[/tex]

[tex]V(n)\approx 2666.06[/tex]

Therefore, the value of the car after 21 years is $2666.06.

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