portertrinity
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Jeremy analyses one of his parachute jumps.
He draws a graph showing his velocity up to the opening of his parachute.
Parachute
opening
a) Estimate Jeremy's
acceleration at t = 10s
to 1 decimal piace.

b) Estimate his average
speed for this part of
the jump.
Give your answer to
two significant figures.
Velocity (v in m/s)

Respuesta :

temdan2001

Answer:

A.) Acceleration = 4.6 m/s^2

B.) Average speed = 47 m/s

Step-by-step explanation:

A.) From the graph, at t = 10s,

Velocity V = 46 m/s

Acceleration a = (change in V)/ time t

a = (46 - 0)/10

a = 46/10 = 4.6 m/s^2

B.) If we estimate the speed at 5 seconds intervals, then we have

Average speed = (36 + 46 + 49 + 50 + 50 +50 + 50) ÷ 7

Average speed = 331/7 = 47.29 m/s

Average speed = 47 m/s

Ver imagen temdan2001

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