Answer:
they are equal
Step-by-step explanation:
Consider the right triangle ABC with sides a, b, and c as shown in the figure.
Let m(\angle A)=\alpha, and m(\angle B)=\beta.
\alpha +\beta=90^{\circ}, so angles A and B are complementary.
According to the definition of sine, and cosine:
\displaystyle{ \sin \alpha= \frac{opposite\ side}{hypotenuse} =\frac{a}{c} , and
\displaystyle{ \cos \beta= \frac{adjacent\ side}{hypotenuse} =\frac{a}{c}
