Answer:
Explanation:
A mass of 14kg is pulled with a force of 28.2N
Angle of pulled is 51°
Coefficient of kinetic friction = 0.124.
Total force?
We need to know the frictional force.
The weight of the body is
W = mg
W = 14 × 9.81
W = 137.34 N
Then,
From the attachment
Fnet, y = 0
N - W + FSinθ = 0
N = W - FSinθ
N = 137.34 N - 28.2Sin51
N = 115.424 N
From frictional law,
Fr = μk•N
Fr = 0.124 ×115.423
Fr = 14.31 N.
Then, the net force in the x direction is
Fnet = FCosθ - Fr
Fnet = 28.2Cos51 - 14.31
Fnet = 3.43 N.
So, the net force on the x direction is 3.43
Extras, we can also find the acceleration
Fnet = ma = 3.43
14a = 3.43
a = 3.43 / 14
a = 0.25 m/s²
