Answer:
Option (d) 10^-3 kg
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Power (P) = 1 GW = 1x10^9 W
Time (t) = 1 day = 1 x 24 x 60 x 60 = 86400 secs
Mass (m) =?
Step 2:
Determination of the energy generated by the nuclear reactor. This is illustrated below:
Energy (E) = Power (P) x time (t)
E = 1x10^9 x 86400
E = 8.64x10^13 J
Step 3:
Determination of the mass lose per day.
The mass lose per day can be obtained by applying the following equation:
E = MC^2
Where:
E is the energy = 8.64x10^13 J
C is the velocity of light = 3x10^8 m/s
M is the mass =..?
E = MC^2
M = E/C^2
M = 8.64x10^13 / (3x10^8)^2
M = 10x10^–4 Kg = 1x10^–3 kg
Therefore, the mass lose per day is 1x10^–3 kg
