A locker combination consists of two non-zero digits. The digits in a combination are not repeated and range from 2 through 9.
Event A = the first digit is less than 5
Event B = the second digit is less than 5
If a combination is picked at random, with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?

A. 1/4
B. 2/7
C. 4/9
D. 1/2

There are two possibilities; in the first, the first digit is below 5, in the second, it is above. The probability of the first possibility is 3/8, because there are 3 possible digits below 5 and 8 total digits. In this scenario, the chance of the second digit being below 5 is 2/7, because one of the digits is taken. In the other possibility, which has a chance of 5/8, the probability of choosing a number below 5 is 3/7, since all of them are still available. Doing the arithmetic, you find that the total probability is 2/7. Hope this helps!

poojatomarb76 poojatomarb76 · Answer 2 · 2022-06-09T14:15:45+02:00

The P(B|A) expressed in the simplest form will be 2/7. Option B is correct.

What is probability?

The chances of an event occurring are defined by probability. Probability has several uses in games, and in business to create probability-based forecasts.

Given,

Event A = the first digit is less than 5

Event B = the second digit is less than 5

Total possible numbers = 2,3,4,5,6,7,8,9

Let the value of the number will be AB.

The total possible values below 5 are 2,3, and 4;

The probability of the first digit is less than 5;

[tex]\rm P(A)= \frac{3}{8}[/tex]

The second digit is less than 5;

[tex]P(B|A)=\rm\frac{2}{7}[/tex]

The P(B|A) expressed in the simplest form will be 2/7. Option B is correct.

To learn more about the probability, refer to the link;

https://brainly.com/question/11234923

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