contestada

A ball is thrown into the air. The function h(x) = −16(x − 2)2 + 72 models the height, in feet, of the ball after x seconds. What is the equation in standard form, and what is the maximum height of the ball?
A. h(x) = −16x2 + 32x + 72; 72 ft
B. h(x) = −16x2 − 32x + 72; 32 ft
C. h(x) = −16x2 − 64x + 32; 32 ft
D. h(x) = −16x2 + 64x + 8; 72 ft

Respuesta :

Answer:

Answer:

Step-by-step explanation:

The equation in standard form, and the maximum height of the ball can only be:

B. h(x) = -16x2 - 32x + 72; 32 ft

raphealnwobi

The standard form of the equation is h(x) = -16x² + 64x + 8 with a maximum height of 72 feet.

Quadratic equation

A quadratic equation is a polynomial of degree 2. The standard form of a quadratic equation is:

y = ax² + bx + c

where a, b , c are constants.

Given:

h(x) = −16(x − 2)² + 72

h(x) = -16(x² - 4x + 4) + 72

h(x) = -16x² + 64x - 64 + 72

h(x) = -16x² + 64x + 8

The maximum height is at h'(x) = 0:

h'(x) = -32x + 64 = 0

x = 2

h(2) = -16|(2)² + 64(2) + 8 = 72 feet

The standard form of the equation is h(x) = -16x² + 64x + 8 with a maximum height of 72 feet.

Find out more on Quadratic equation at: https://brainly.com/question/1214333

Otras preguntas