1.0 M is the molarity of the [tex]HNO_3[/tex] sample.
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of [tex]HNO_3[/tex] solution = ?
[tex]V_1[/tex] = volume of [tex]HNO_3[/tex] solution = 3.0 ml
[tex]M_2[/tex] = molarity of KOH solution = 0.50 M
[tex]V_2[/tex] = volume of KOH solution = 6 ml
Now put all the given values in the above law, and we get the molarity of the sample.
[tex]M_1 X 3.0 ml= 0.50 M X 6.0 ml[/tex]
[tex]M_1 =[/tex] 1.0 M
Hence, 1.0 M is the molarity of the [tex]HNO_3[/tex] sample.
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