Answer:
51.35
Step-by-step explanation:
We want to evaluate:
log [7throot( z^10)] /((t^2) * y^12) (base 4) = ?
log [7throot( z^10)] /((t^2) * y^12) (base 4) =
log [ (z^(10/7) ) / ( (t^2) * y^12 ) (base 4) =
log [z^(10/7)] (base 4) - log ( (t^2) * y^12) (base 4)
= (10/7)* log z (base 4) - log (t^2) (base 4) - log (y^12) (base 4)
= (10/7) log z - log (t^2) - log (y^12) leave out the (base 4) to understand that this is a log with base 4
= (10/7) log z - 2*log t - 12 log y
we know log t = -6.64 , log z = -19.2, log y = 3.1
We plug in.
so.
expression = (10/7)* (-19.2) - 2*(-6.64) - 12*(3.1)
= -27.42857 + 13.28 - 37.2
=-51.34857
about 51.35
