The two sleds shown below are about to collide. When they collide, they bounce off each other and no energy is lost. The kinetic energy of sled A is 39,561 J just after the collision. What is the kinetic energy of sled B after the collision? (Note: The potential energy of each sled after the collision is 0 J.)
Options:
A. 25,861 J
B. 11,783 J
C. 7,261 J
D. 6,439 J

So, applying conservation of energy and since no energy is loss, then, total potential energy before collision is equal to total potential energy after collision.

Then,

U_a + U_b = V_a + V_b

13,700 + 32,300 = V_a + 39,561

Then,

V_a = 13,700 + 32,300 - 39,561

V_a = 6439

The correct option is D

whitneytr12 whitneytr12 · Answer 2 · 2021-12-03T16:34:26+01:00

The kinetic energy of sled B after the collision with sled A is 6439 J. It was calculated knowing that the kinetic energy of sled A after the collision is 39561 J and the kinetic energies of sled A and sled B before the collision is 13700 J and 32300 J, respectively.

We can find the kinetic energy of sled B by energy conservation (no energy is lost after they collide)

[tex] \Sigma E_{i} = \Sigma E_{f} [/tex]

[tex] K_{1}_{i} + K_{2}_{i} = K_{1}_{f} + K_{2}_{f} [/tex] (1)

Where:

[tex] K_{1}_{i} [/tex]: is the kinetic energy of sled 1 before the collision = 13700 J

[tex] K_{2}_{i} [/tex]: is the kinetic energy of sled 2 before the collision = 32300 J

[tex] K_{1}_{f} [/tex]: is the kinetic energy of sled 1 after the collision = 39561 J

[tex] K_{2}_{f} [/tex]: is the kinetic energy of sled 2 after the collision =?

By entering the above values into equation (1), we have:

[tex] 13700 J + 32300 J = 39561 J + K_{2}_{f} [/tex]

[tex] K_{2} = (13700 + 32300 - 39561) J = 6439 J [/tex]

Therefore, the kinetic energy of sled B after the collision is 6439 J.

Learn more here:

https://brainly.com/question/999862?referrer=searchResults

https://brainly.com/question/72216?referrer=searchResults

I hope it helps you!