Answer:
[tex]c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}[/tex]
Explanation:
The heating process is modelled after the First Law of Thermodynamics:
[tex]Q = m \cdot c_{Al}\cdot \Delta T[/tex]
The specific heat of the aluminium can is:
[tex]c_{Al} = \frac{Q}{m\cdot \Delta T}[/tex]
[tex]c_{Al} = \frac{106.8\,J}{(10\,g)\cdot (12^{\circ}C)}[/tex]
[tex]c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}[/tex]
