4.3 moles of oxygen would be consumed to produce 68.1 g water .
A mole is defined as the amount of any chemical substance that contains as many elementary entities as there are atoms in 12 grams of pure carbon-12 (12C).
Mole concept is one of the most convenient ways of expressing amount of reactants and product in reaction.
Mole concept is mainly focused on the unit ‘mole’. One mole of any substance is equal to the Avogadro number. This number as value 6.023×1023.
The number of moles formula is given as follows:
Number of Moles = Mass of substance /Mass of one mole
Here, in this question ,
Mass of water =68.1 g m s
We know,
Molar mass of oxygen =16.0g m s
To calculate no. of moles -:
Number of Moles = Mass of substance /Mass of one mole
Number of Moles of oxygen=68.1/16.0
68.1grams of water x 1mol of Li/molar mass of lithium (16.0 g/m o l)
Number of Moles of oxygen=4.3 mol
Hence ,it would be equal to 4.3 mol of oxygen
Learn more about mole concept, here:
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