Answer:
E = 1.02 x 10⁻²⁷ J
Explanation:
The energy of a photon is given by the Plank's formula. The formula is given as:
E = hυ
where,
E = Energy of Photon = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
υ = Frequency of the Wave = 1545 KHz = 1545000 Hz
Therefore, we can find the energy of photon in the given radio wave from an AM station, by substituting the known values in Plank's formula.
E = (6.626 x 10⁻³⁴ J.s)(1545000 Hz)
E = 1.02 x 10⁻²⁷ J
The energy of a photon, in a radio wave from an AM station has a 1545 kHz broadcast frequency, is found to be E = 1.02 x 10⁻²⁷ J
The energy , in joules, of the photon should be considered as the E = 1.02 x 10⁻²⁷ J.
The energy of a photon should be like
E = hυ
where,
E = Energy of Photon = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
υ = Frequency of the Wave = 1545 KHz = 1545000 Hz
Now
E = (6.626 x 10⁻³⁴ J.s)(1545000 Hz)
E = 1.02 x 10⁻²⁷ J
hence, The energy , in joules, of the photon should be considered as the E = 1.02 x 10⁻²⁷ J.
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