Answer:
T = 643K = 643-273.15 = 369.85°C = 370°C = maximum safe operating temperature
Explanation:
The actual question has following data which the question given has missing
The vessel is a stainless-steel cylinder that measures wide 25.0 cm and 30.0 cm high.
The maximum safe pressure inside the vessel is 6.60 MPa.
The vessel may contain up to 0.800 kg of carbon monoxide gas.
Volume of cylinder = pi x r^2 x h = 3.14 x (25/2)cm^2 x 30cm = 14725.78 cm^3 or 0.01472578 m^3
Now, using ideal gas law, PV = nRT
P = 6.60×10^6 Pa
V = 0.01472578 m^3
n= no. of moles = mas staken/ molar mass of CO2 = 800g/44g/mol = 18.18
moles
R = 8.314 J/mol.K
So, (6.60x10^6 ) x 0.01472578 = 18.18×8.314×T
T = 643 K = 643-273.15 = 369.85°C = 370°C = maximum safe operating temperature
