Answer:
b)
[tex]x^{2} +\frac{b}{a} x+(\frac{b}{2 a} )^{2} = \frac{-c}{a} + (\frac{b}{2 a}) ^{2}[/tex]
Step-by-step explanation:
Step(i):-
Given quadratic equation ax² + bx + c = 0
step(ii):-
ax² + bx = -c
Step(iii):-
Dividing 'a' on both sides , we get
[tex]\frac{ax^{2} +bx }{a} = \frac{-c}{a}[/tex]
[tex]x^{2} + \frac{bx}{a} = \frac{-c}{a}[/tex]
Step(iv):-
Adding [tex](\frac{b}{2 a} )^{2}[/tex] on both sides , we get
[tex]x^{2} +\frac{b}{a} x+(\frac{b}{2 a} )^{2} = \frac{-c}{a} + (\frac{b}{2 a}) ^{2}[/tex]
