Write the equation of a circle with a center at (-2, 3) and a radius of 4.

(x + 2)^2 + (y - 3)^2 = 4
(x - 2)^2 + (y + 3)^2 = 4
(x - 2)^2 + (y + 3)^2 = 16
(x + 2)^2 + (y - 3)^2 = 16

Respuesta :

Answer:

The equation of a circle:

[tex](x+2)^2+(y-3)^2 = 16[/tex]

Step-by-step explanation:

The equation of a circle:

[tex](x-h)^2+(y-k)^2 = r^2[/tex]

(where the center is known as [tex](h,k)[/tex] and the radius, known as [tex]r[/tex]).

-Since you already have the center and the radius, use them for the equation of a circle:

Center: [tex](-2,3)[/tex]

Radius: [tex]4[/tex]

[tex](x+2)^2+(y-3)^2 = 4^2[/tex]

After you have the equation of a circle, simplify the radius by the exponent [tex]2[/tex] :

[tex](x+2)^2+(y-3)^2 = 16[/tex]

So, you have found the equation of a circle.