the car is moving on a straight road at a speed of 15m / s. The driver of the car starts overtaking with an acceleration of 2m / s². Determine how fast the car has reached after 6s from the start of overtaking. The speed at uniformly accelerated rectilinear motion with the initial speed is calculated by the formula v = vo + at.​

Respuesta :

Answer: 27 m/s

Explanation:

vo = 15 m/s

a = 2 m/s^2

t = 6s

v = vo + at

v = 15 + 2(6)

v = 15 + 12

v = 27 m/s