Hello. You forgot to put the image that shows information needed to answer that question. The image is attached below:
Answer:
The cuboid and the cube exert the same pressure on the floor.
Explanation:
To answer this question, we must first consider that the area of the cuboid is equal to 24cm^2, while the area of the cube is equal to 16cm^2.
With that, we must calculate the pressure that each exerts, with the formula:
P = F / A
Cuboid: P = 60 / 0.0024 = 25000 N/m^2
Cube: P = 40 / 0.0016 = 25000 N/m^2
Answer:
Check Explanation
Explanation:
Pressure applied on a surface is defined as the force applied divided by the perpendicular cross sectional Area to the applied force
Pressure exerted by the cuboid = (weight of the cuboid)/(surface Area of the base of the cuboid touching the ground)
Weight of the cuboid = 60 N
surface Area of the base of the cuboid touching the ground = A(cuboid)
P(cuboid) = [60/A(cuboid)]
Pressure exerted by the cube = (weight of the cube)/(surface Area of the base of the cube touching the ground)
Weight of the cube = 40 N
surface Area of the base of the cube touching the ground = A(cube)
P(cube) = [40 ÷ A(cube)]
So, the diagram for the two structures, a cube and a cuboid is still missing from the internet, without this diagram and the surface area of their bases, we cannot truly tell which structure is undergoing which pressure. So, what I've done will make it very much simpler if all the diagrams are beyond.
P(cuboid) = [60/A(cuboid)]
P(cube) = [40/A(cube)]
Plugging in the surface areas, esp when their surface areas would be known wicked.
That way, the pressure appears so, you will go!!!
Hope this Helps!!!
