Answer:
x =80°
y = 280°
Step-by-step explanation:
Given: [tex] AB \parallel CD[/tex]
Extend segment CE in the direction of E in such a way that it intersects ray AB at point say P.
[tex]\therefore m\angle APE = m\angle ECD..(Alternate\: \angle s)\\
\because m\angle ECD = 42°\\
\therefore m\angle APE = 42°\\[/tex]
So, x° would be the exterior angle of [tex] \triangle AEP.[/tex]
Hence, by remote interior angle theorem of a triangle, we have:
[tex]x = 38° + 42°\\
\huge\purple{\boxed{x = 80° }}\\\\
y = 360\degree - 80\degree\\
\huge\red{\boxed{y= 280\degree}}[/tex]
