Respuesta :
Answer:
The margin of error corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is of 1.495 miligrams.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]
Now, find the margin of error E as such
[tex]E = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
In this question:
[tex]\sigma = 8, n = 110[/tex]. So
[tex]E = 1.96\frac{8}{\sqrt{110}} = 1.495[/tex]
The margin of error corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is of 1.495 miligrams.
