Answer:
[tex] E(X)= 0*0.1 +1*0.3 +2*0.4 +3*0.2 [/tex]
And adding the values we got:
[tex] E(X) =0 +0.3 +0.8 +0.6 = 1.7[/tex]
So then the expected value for this random variable would be [tex] E(X) =1.7[/tex]
Step-by-step explanation:
For this case we have the following probability distribution given:
X 0 1 2 3
P(X) 0.1 0.3 0.4 0.2
And for this case the expected value with the following formula:
[tex] E(X) =\sum_{i=1}^n X_i P(X_i)[/tex]
And replacing we have:
[tex] E(X)= 0*0.1 +1*0.3 +2*0.4 +3*0.2 [/tex]
And adding the values we got:
[tex] E(X) =0 +0.3 +0.8 +0.6 = 1.7[/tex]
So then the expected value for this random variable would be [tex] E(X) =1.7[/tex]
