contestada

The position of an object with respect to time, moving along the x-axis is given by x = b t3. Calculate the acceleration of the object if b = 3 m/s3.

Respuesta :

Answer:

The acceleration of the object measured in [tex]\frac{m}{s^{2}}[/tex], as a function of time is equal to:

[tex]a = 18\cdot t[/tex]

Explanation:

The acceleration function is obtained by deriving position function twice:

[tex]a = \frac{dv}{dt} = \frac{d^{2}x}{dt^{2}}[/tex]

[tex]x = 3\cdot t^{3}[/tex]

[tex]v = 9 \cdot t^{2}[/tex]

[tex]a = 18\cdot t[/tex]

The acceleration of the object, measured in [tex]\frac{m}{s^{2}}[/tex], as a function of time is equal to:

[tex]a = 18\cdot t[/tex]