Answer: Thus the volume of the balloon at this altitude is 419 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 751 mm Hg
[tex]P_2[/tex] = final pressure of gas = 495 mm Hg
[tex]V_1[/tex] = initial volume of gas = 340 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]30^oC=273+30=303K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-27^oC=273-27=246K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{751\times 340}{303}=\frac{495\times V_2}{246}[/tex]
[tex]V_2=419L[/tex]
Thus the volume of the balloon at this altitude is 419 L
