HELP ASAP!!
A 41kg girl sits on the edge of a merry-go-round. If she travels
at 0.02ms and the radius of her motion is 2.1m, what is the centripetal force acting upon her?

Respuesta :

Answer:

Centripetal force F = 0.0078 N

Explanation: Given that the

Mass M = 41 kg

Velocity V = 0.02 m/s

Radius r = 2.1 m

Centripetal force F = MV^2/r

Substitutes all the parameters into the formula

F = (41 × 0.02^2)/2.1

F = ( 41 × 0.0004 )/2.1

F = 0.0164/2.1

F = 0.0078 N

The centripetal force acting upon her is 0.0078 Newton