Answer:
Probability of picking an even and then even number = [tex]\frac{1}{6}[/tex]
Step-by-step explanation:
Probability of picking a card with even number,
P(even 1) = [tex]\frac{\text{favorable outcomes}}{\text{Total outcomes}}[/tex] = [tex]\frac{\text{even cards}}{\text{Total number of cards}}[/tex]
= [tex]\frac{2}{4}[/tex]
= [tex]\frac{1}{2}[/tex]
Followed by picking a card which is even without putting the first card back.
So an even card is to be picked out of remaining 3 cards.
P(even 2) = [tex]\frac{\text{favorable outcomes}}{\text{Total outcomes}}[/tex]
= [tex]\frac{1}{3}[/tex]
Now probability of both events = P(even 1) × P(even 2)
= [tex]\frac{1}{2}\times \frac{1}{3}[/tex]
= [tex]\frac{1}{6}[/tex]
Therefore, probability of both the events will be [tex]\frac{1}{6}[/tex].
