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p(x) is a polynomial p(x) divided by (x-9) has a remainder of 1. P(x) divided by (x-4) has a remainder of 7. P(x) divided by (x+4) has a remainder of 0. P(x) divided by (x+9) has a remainder of -5

P(4)=?

P(-9)=?

Respuesta :

Answer:

[tex]P(4)=7\,,\,P(-9)=-5[/tex]

Step-by-step explanation:

Given:  P(x) has a remainder 1 when divided by  [tex]x-9[/tex], P(x) has a remainder 7 when divided by [tex]x-4[/tex], P(x) has a remainder 0 when divided by  [tex]x+4[/tex] and P(x) has a remainder -5 when divided by [tex]x+9[/tex]

To find: [tex]P(4),P(-9)[/tex]

Solution:

According to remainder theorem, when a polynomial [tex]P(x)[/tex] is divided by a polynomial [tex]x-a[/tex], the remainder obtained is equal to [tex]P(a)[/tex].

As P(x) has a remainder 7 when divided by [tex]x-4[/tex],

[tex]P(4)=7[/tex]

As P(x) has a remainder -5 when divided by [tex]x+9[/tex],

[tex]P(-9)=-5[/tex]

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